Question 186527This question is from textbook
: 6. A bag of colored marbles holds 75 blue marbles, 44 red marbles and 21 white marbles.
a. What is the probability that in selecting one marble and then a second marble without replacing the first marble that both marbles will be red?
b. Four marbles are selected, one at a time, without replacement. What is the probability that the first marble will be red, the second will be white, the third marble will be red and the last marble will be blue?
This question is from textbook
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! 75 blue
44 red
21 white
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140 total number of marbles.
a) 44/140*43/139=.3143*.309=.097 or 9.1 % probability of selecting 2 red marbles.
b) 44/140*21/139*43/138*75/137
.314*.15*.312*.547=.0081 or .81 % probability of selecting a red, then a white, then another red, then a blue marble without replacement.
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