SOLUTION: If four out of five doctors prefer fast food, than at a convention of 455 doctors, how many probably ate fast food for lunch? Set up an equation and solve. thanks thanks

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Question 178217: If four out of five doctors prefer fast food, than at a convention of 455 doctors, how many probably ate fast food for lunch? Set up an equation and solve.
thanks thanks
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If four out of five doctors prefer fast food, than at a convention of 455 doctors, how many probably ate fast food for lunch? Set up an equation and solve.
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Let x = # preferring fast food
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Equation:
x = (4/5)455 = 4*91 = 364
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Cheers,
Stan H.