SOLUTION: A weight of 250g stretches a spring to a distance of 9.5 cm. If the distance stretched is directly proportional to the attached weight, what weight will stretch the spring to 5.7cm

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Question 161986: A weight of 250g stretches a spring to a distance of 9.5 cm. If the distance stretched is directly proportional to the attached weight, what weight will stretch the spring to 5.7cm?
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
A weight of 250g stretches a spring to a distance of 9.5 cm. If the distance stretched is directly proportional to the attached weight, what weight will stretch the spring to 5.7cm?

The vertical spring formula is

W+=+kx

where W = the weight placed on the spring,
      k = the spring constant
      x = the distance in cm the spring stretches when
a weight of W grams is placed on it.

We don't know the spring constant.  We find it from

>>...A weight of 250g stretches a spring to a distance of 9.5 cm...<<

So we substitute W=250 and x=9.5 into W+=+kx:

W+=+kx
250+=+k%289.5%29
Divide both sides by 9.5
250%2F9.5=k
26.31578947=k

Now we substitute k=26.31578947 into the spring formula:

W=kx

W=26.31578947x

Now our formula is complete and we can now solve the problem
asked for:

>>...what weight will stretch the spring to 5.7cm?...<<

Substitute x=5.7 into the complete formula W=26.31578947x

W=26.31578947x
W=26.31578947%285.7%29
W=150grams

Edwin