SOLUTION: find two consecutive even integers such that three times the first equals twice the second

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Question 1009132: find two consecutive even integers such that three times the first equals twice the second
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be some integer. The expression 2x represents any even integer. The next even integer after 2x is 2x+2

so we have

first even integer: 2x
second even integer: 2x+2

the two even integers are as close as possible.


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three times the first equals twice the second

3*(first) = 2*(second)

3*2x = 2*(2x+2)

6x = 4x + 4

6x - 4x = 4

2x = 4

x = 4/2

x = 2


If x = 2, then 2x = 2*2 = 4 and 2x+2 = 2*2+2 = 6

The two consecutive even integers are 4 and 6