Tutors Answer Your Questions about Word Problems With Coins (FREE)
Question 405938: Ben invested $800, part at 9% per annum and the rest at 12% per annum. After one year the total interest earned was $79.50. How much did he invest?
we are solving them by elimination (gr 11)
i dont know how to do this one at all.
Click here to see answer by mananth(16949)  |
Question 406121: The office manager for a small law firm made the weekly postage purchase. He bought regular .37 stamps for most of the firm, but he also picked up some .40 breast cancer stamps at the request of some lawyers. He noticed that the number of breast cancer stamps was 8 fewer than the number of regular stamps and he spent $19.90. How many of each stamp did he buy?
Click here to see answer by ewatrrr(24785)  |
Question 408216: the value of an uncirculated mint state-65 1950 jefferson nickel minted in denver is 5/4 the value a 1945 nickel minted in philadelphia in similar condition. together the total value of the two coins is 36.00 dollars. what is the value of each coin?
Click here to see answer by rfer(16322) |
Question 408216: the value of an uncirculated mint state-65 1950 jefferson nickel minted in denver is 5/4 the value a 1945 nickel minted in philadelphia in similar condition. together the total value of the two coins is 36.00 dollars. what is the value of each coin?
Click here to see answer by ewatrrr(24785)  |
Question 409090: I need help with a word problem. This is what I have so far:
Joe has a collection of nickels and dimes that is worth $3.95. If the number of dimes was doubled and the number of nickels was increased by 21, the value of the coins would be $8.40. How many nickels and dimes does he have?
first part:
dimes value + nickles value = total amount
(value of a dime)(# of dimes) + (value of a nickle)(# of nickles) = total amount
(0.10)(# of dimes) + (0.05)(# of nickles) = 3.95
(0.10)(d) + (0.05)(n) = 3.95
so d = number of dimes we start with
n = number of nickles we start with
second part:
dimes value + nickles value = total amount
(value of a dime)(# of dimes) + (value of a nickle)(# of nickles) = total amount
(0.10)(2*d) + (0.05)(n + 21) = 8.40
because we're supposed to have double (*2 the dimes) and 21 more nickles
The two equations are then:
(0.10)(d) + (0.05)(n) = 3.95
(0.10)(2d) + (0.05)(n + 21) = 8.40
Click here to see answer by solver91311(24713)  |
Question 410157: Joe has a collection of nickles and dimes that is worth $8.55. If the number of dimes is tripled and the number of nickles is decreased by 2, the value of the coins would be $23.45. how many nickles and dimes does he have. Please show your work.
Click here to see answer by scott8148(6628)  |
Question 416299: I need help on this problem. Lisa's piggy bank contained 21 dimes, nickels, and pennies. The total in the piggy bank was $1.21. Lisa removed all the dimes from the piggy bank. This left only 41 cents in the bank. How many pennies were in the bank? I did three equations:
d+n+p=21
10d+5n+1p=121
5n+1p=41
I tried to subtract the frist two equations first, then work with the answer I got and tried to subtract the third one. Can you please show me how it's done correctly.
Click here to see answer by stanbon(75887) |
Question 416299: I need help on this problem. Lisa's piggy bank contained 21 dimes, nickels, and pennies. The total in the piggy bank was $1.21. Lisa removed all the dimes from the piggy bank. This left only 41 cents in the bank. How many pennies were in the bank? I did three equations:
d+n+p=21
10d+5n+1p=121
5n+1p=41
I tried to subtract the frist two equations first, then work with the answer I got and tried to subtract the third one. Can you please show me how it's done correctly.
Click here to see answer by Edwin McCravy(20081)  |
Question 417331: A donation box contains 49 coins consisting of nickels, dimes, and quarters. The number of quarters is two more than twice the number of dimes. The total value of the coins is $3.30. Find the number of nickles, dimes, and quarters.
Click here to see answer by ewatrrr(24785)  |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155
|