SOLUTION: A newspaper carrier has $3.90 in change. He has three more quarters than dimes but five times as many nickels as quarters. How many coins of each type doe he have?
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Question 992525: A newspaper carrier has $3.90 in change. He has three more quarters than dimes but five times as many nickels as quarters. How many coins of each type doe he have? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A newspaper carrier has $3.90 in change. He has three more quarters than dimes but five times as many nickels as quarters. How many coins of each type does he have?
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5n + 10d + 25q = 390 cents
q = d + 3
n = 5q
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Substitue for d and n and solve for "q"::
5(5q) + 10(q-3) + 25q = 390
25q + 10q - 30 + 25q = 390
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60q = 420
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q = 7 (# of quarters)
d = q-3 = 4 (# of dimes)
n = 5q = 35 (# of nickels)
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Cheers,
Stan H.
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