SOLUTION: I have pennies, nickels, and dimes. If 2 times the amount of quarters is dimes, and there's 2 nickles more than there are quarters. The total amount is $7.60. how many of each coin

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: I have pennies, nickels, and dimes. If 2 times the amount of quarters is dimes, and there's 2 nickles more than there are quarters. The total amount is $7.60. how many of each coin      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 989668: I have pennies, nickels, and dimes. If 2 times the amount of quarters is dimes, and there's 2 nickles more than there are quarters. The total amount is $7.60. how many of each coin do i have? explain your answer.
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
I went through a solution process earlier, but then thought more about the description, and decided not to try to finish.

You "have" pennies, nickels and dimes;
and then you have a description involving quarters.
What is the exact problem description, word-for-word?

NO PENNIES; QUARTERS INSTEAD.
q, d, n, quarters nickels dimes
system%28d=2q%2Cn=q%2B2%2C0.25q%2B0.1d%2B0.05n=7.60%29

Multiply the money equation by 20.
5q%2B2d%2Bn=152
Substitute the other relationships described.
5q%2B2%282q%29%2B%28q%2B2%29=152
Solve for q first ; and then go back to the other two relationships to evaluate d and n.