A family has a coin jar that is now full. The children count the change and calculate the total value to be $44.08.
Let Q represent the number of quarters and use
Let's also let each coin be represented by the 1st letter in the spelling of
the coin:
The children count the change and calculate the total value to be $44.08,
that's the same as 4408 cents.
25Q + 10D + 5N + P = 4408
There are:
151 more dimes than quarters
D = Q + 151
8 times as many nickels as quarters
N = 8Q
15 more than 18 times as many pennies as quarters
P = 18Q + 15
25Q + 10D + 5N + P = 4408
D = Q + 151
N = 8Q
P = 18Q + 15
In the first equation substitute for D, N, and P
25Q + 10D + 5N + P = 4408
| | | | | |
25Q + 10(Q + 151) + 5(8Q) + 18Q + 15 = 4408
Solve that equation for Q, then find D, N, and P by substituting
what you get for Q in these three equations:
D = Q + 151
N = 8Q
P = 18Q + 15
I won't tell you the answers but there are 1034 coins total. So
when you get your answers add them up and see if you get 1034.
Edwin
