SOLUTION: A student has some nickels and dimes. He has a total of 71 coins worth $4.95. How many of each coin does he have?

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Question 945424: A student has some nickels and dimes. He has a total of 71 coins worth $4.95. How many of each coin does he have?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
N%2BD=71
5N%2B10D=495
From eq. 1,
5N%2B5D=5%2871%29=355
5N=355-5D
Substitute into eq. 2,
355-5D%2B10D=495
5D=140
D=28%7D%7D%0D%0AThen%2C%0D%0A%7B%7B%7BN%2B28=71
N=43