SOLUTION: Michael had $5.25 in nickels and quarters. If he had 15 more nickels than quarters, how many coins of each type did he have?

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Question 936665: Michael had $5.25 in nickels and quarters. If he had 15 more nickels than quarters, how many coins of each type did he have?

Found 2 solutions by ewatrrr, TimothyLamb:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x the number of Quarters (25 CENTS in a each Qarter)
25x + 5(x+15) = 525cents (CENTS makes Sense)
30x = 450
x = 15, number of Quarters. Nickels 30 15%2B15
....
Checking..
25(15) + 5(30) = 375 + 150 = 525cents or $5.25

Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
x = number of nickels
y = number of quarters
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5x + 25y = 525
x = y + 15
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put the system of linear equations into standard form
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5x + 25y = 525
x - y = 15
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = number of nickels = 30
y = number of quarters = 15
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