Question 933807: A man has $185 in five and ten dollar Gills, how many of each did he has if he had 7 more fives than tens?
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! x = number of ten dollar bills
x + 7 = number of five dollar bills {he has 7 more fives than tens}
10x + 5(x + 7) = 185 {value of bill times number of bills equals total value}
10x + 5x + 35 = 185 {used distributive property}
15x + 35 = 185 {combined like terms}
15x = 150 {subtracted 35 from each side}
x = 10 {divided each side by 15}
x + 7 = 17 {substituted 10, in for x, into x + 7}
10 ten dollar bills
17 five dollar bills
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