A collection of 15 coins is worth $1.00. If the coins are dimes and nickels, how many of each coin are there?
I have only been taught to do it when you are told that one of the coins has more than the other. Not sure how to set this up
Method 1: Solving for 2 unknowns
Let number of dimes and number of nickels, be D and N, respectively. Then we have:
D + N = 15 --------- Denomination-number equation
.1D + .05N = 1 --------- Denomination-value equation
Solve for D or N and substitute solved variable into either equation to determine value of other variable
Method 2: Solving for 1 unknown
Let number of dimes, be D
Then number of nickels = 15 - D. We now have:
.1D + .05(15 - D) = 1 -------- Value equation
Solve for D, and then SUBTRACT that value from 15 (total number of coins) to determine number of nickels
Then do a check!!
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