SOLUTION: please help me solve this problem. together ken and Amy have 36 coins. ken has 4 more coins than Amy. how many cons does Amy have? please and thank you.

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Question 904597: please help me solve this problem. together ken and Amy have 36 coins. ken has 4 more coins than Amy. how many cons does Amy have? please and thank you.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let' the number of coins Ken has be x and the number of coins Amy has be y
Ken and Amy have 36 coins:
x%2By=36 ....eq.1
Ken has 4 more coins than Amy:
x=y%2B4 ...eq.2
go to
x%2By=36 ....eq.1 and substitute x from eq.2
y%2B4%2By=36 ...solve for y
2y=36-4
2y=32
y=32%2F2
highlight%28y=16%29......the number of coins Amy has
now find x

x=y%2B4 ...eq.2
x=16%2B4
highlight%28x=20%29 ....the number of coins Ken has