SOLUTION: Please help me solve this,
a coin collector has 2.45 in nickels and dimes. She has 5 times as many nickels as dimes. How many does she have of each coin?
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a coin collector has 2.45 in nickels and dimes. She has 5 times as many nickels as dimes. How many does she have of each coin?
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Question 733000: Please help me solve this,
a coin collector has 2.45 in nickels and dimes. She has 5 times as many nickels as dimes. How many does she have of each coin?
123408@houndmail.macc.edu Found 3 solutions by lynnlo, ikleyn, josgarithmetic:Answer by lynnlo(4176) (Show Source):
You can put this solution on YOUR website! .
a coin collector has 2.45 in nickels and dimes. She has 5 times as many nickels as dimes.
How many does she have of each coin?
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This problem is ideal to solve it mentally, without using equations.
Indeed, according to the problem, we can group the coins in sets,
each containing 5 nickels and one dime.
Each such set is worth 5*5 + 10 = 35 cents.
Hence, the number of sets is = 7.
So, the coin collector has 7 dimes and 5*7 = 35 nickels.
CHECK. 7*10 + 35*5 = 245 cents = $2.45. ! correct !
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