SOLUTION: "Jimmy had $5.25 in nickels and quarters. If he had 15 more nickels than quarters, how many coins of each type did he have?" HELP ME PLEASE!!!!
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Question 67484: "Jimmy had $5.25 in nickels and quarters. If he had 15 more nickels than quarters, how many coins of each type did he have?" HELP ME PLEASE!!!! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Jimmy had $5.25 in nickels and quarters. If he had 15 more nickels than quarters, how many coins of each type did he have?
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Let number of quarters be "x" ; Value of these is 25x cents
Number of nickels is "x+15" ; Value of these is 5(x+15)=5x+75 cents
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EQUATION:
value + value = 525 cents
25x + 5x+75 = 525
30x=450
x=15 (this is the number of quarters)
x+15=30 (this is the number of nickels)
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Cheers,
Stan H.
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