SOLUTION: nick has $3.85 in dimes quarters. if he has 7 more dimes than quarters,how many each coin does he have?

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Question 666459: nick has $3.85 in dimes quarters. if he has 7 more dimes than quarters,how many each coin does he have?
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
x = dimes
y = quarters
...
Given
.1x + .25y = 3.85
x = y + 7
...
Substitute x into the first equation and solve for y, quarters
.1(y+7) + .25y = 3.85
...
Distribute .1
.1y + .7 + .25y = 3.85
...
Isloate y
.35y = 3.85 - .7
.35y = 3.15
...
Divide both sides by .35
highlight_green%28y+=+9+%29 quarters
...
Substitute y = x-7 into the first equation and solve for x, dimes
.1x + .25(x-7) = 3.85
...
Distribute the .25
.1x + .25x - 1.75 = 3.85
...
Isolate x
.35x = 3.85 + 1.75
.35x = 5.6
highlight_green%28x+=+16%29 dimes
...
Check cartoon%28%0D%0A.1%2816%29+%2B+.25%289%29%2C%0D%0A1.60+%2B+2.25%2C%0D%0A3.85%29
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