SOLUTION: Abby has 36 coins, consisting only of dimes and quarters, worth $7.95. How many dimes and how many quarters does she have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Abby has 36 coins, consisting only of dimes and quarters, worth $7.95. How many dimes and how many quarters does she have?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 649635: Abby has 36 coins, consisting only of dimes and quarters, worth $7.95. How many dimes and how many quarters does she have?
Found 2 solutions by checkley79, josmiceli:
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
.25X+.10(36-X)=7.95
.25X+3.6-.10X=7.95
.15X=7.95-3.6
.15X=4.35
X=4.35/.15
X=29 NUMBER OF QUARTERS.
36-29=7 DIMES.
PROOF:
.25*29+.10*7=4.95
7.25+.70=7.95
7.95=7.95

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
There must be an odd number of quarters, since
the sum ends in a 5. If there was an even number,
it would end in 0.
------------------
I will try 29 quarters. That comes to +29%2A.25+=+7.25+
+7.95+-+7.25+=+.7+ or $.70. That is 7 dimes
+29+%2B+7+=+36+ coins
-------------------
There are 29 quarters and 7 dimes