Question 645738: A box contains nickels, dimes, and quarters worth $2.00.Find all possibilities for the number of each coin if there are three more dimes than quarters.
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
The problem says, "nickels, dimes, and quarters"; all plural, hence there must be at least 2 of any of them.
If there are 2 quarters, then there are 5 dimes making $1.00, so there are 20 nickels.
If there are 3 quarters, then there are 6 dimes making $1.35, so there are 13 nickels.
If there are 4 quarters, then there are 7 dimes making $1.70, so there are 6 nickels.
If there are 5 quarters, then there are 8 dimes making $2.05 -- oops! Too much.
Hence there are exactly three possibliities, 2, 3, or 4 quarters and the resulting number of dimes and nickels.
John
My calculator said it, I believe it, that settles it
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