SOLUTION: A storekeeper goes to the bank to get $10 worth of change. He requests twice as many quarters as half dollars, twice as many dimes as quarters, three times as many nickels as dime

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Question 511343: A storekeeper goes to the bank to get $10 worth of change. He requests twice as many quarters as half dollars, twice as many dimes as quarters, three times as many nickels as dimes, and no pennies or dollars. How many of each coin did the storekeeper get?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +h+ = number of half dollars
Let +q+ = number of quarters
Let +d+ = number of dimes
Let +n+ = number of nickels
given:
(1) +q+=+2h+
(2) +d+=+2q+
(3) +n+=+3d+
(4) +5n+%2B+10d+%2B+25q+%2B+50h+=+1000+ ( in cents )
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There are 4 unknowns and 4 equations, so
it should be solvable.
(1) +q+=+2h+
(1) +h+=+q%2F2+
and
(3) +n+=+3d+
(3) +n+=+3%2A2q+
Now substitute (1) and (2) into (4)
(4) +5%2A6q+%2B+10%2A2q+%2B+25q+%2B+50%2A%28q%2F2%29++=+1000+
(4) +30q+%2B+20q+%2B+25q+%2B+25q+=+1000+
(4) +100q+=+1000+
(4) +q+=+10+
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(1) +h+=+q%2F2+
(1) +h+=+5+
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(2) +d+=+2q+
(2) +d+=+20+
-----------
(3) +n+=+3d+
(3) +n+=+60+
-----------
The storekeeper gets
60 nickels
20 dimes
10 quarters
5 half dollars
check:
(4) +5%2A60+%2B+10%2A20+%2B+25%2A10+%2B+50%2A5+=+1000+
(4) +300+%2B+200+%2B+250+%2B+250+=+1000+
(4) +1000+=+1000+
OK