SOLUTION: If you have 21 more Quarters than Nickels and your total is $15.45, how many of each coin do you have?
I need the Solution and the Algebraic Equation PLEASE
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I need the Solution and the Algebraic Equation PLEASE
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Question 377812: If you have 21 more Quarters than Nickels and your total is $15.45, how many of each coin do you have?
I need the Solution and the Algebraic Equation PLEASE Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! If you have 21 more Quarters than Nickels and your total is $15.45, how many of each coin do you have?
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Equations:
Quantity Eq::: q = n+21
Value Eq::::::5n+25q = 1545 cents
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Substitute for "q" and solve for "n":
5n + 25(n+21) = 1545
30n = 1545-25*21
30n = 1020
n = 34 (# of nickels)
q = n+21 = 55 (# of quarters)
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Cheers,
Stan H.
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