SOLUTION: 35 coins consisting of dimes & nickles. value of coins is $3.30. How many of each type does he have? How is this problem solved? d+n= $3.30

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Question 3403: 35 coins consisting of dimes & nickles. value of coins is $3.30. How many of each type does he have?
How is this problem solved?
d+n= $3.30
Answer by drglass(89) About Me  (Show Source):
You can put this solution on YOUR website!
If d is the number of dimes and n is the number of nickels, then

d+%2B+n+=+35 and

0.1%2Ad+%2B+0.05%2An+=+3.3

subtract n from both sides of the first equation to get d+=+35+-+n and substitute d into the second equation.

0.1%2A%2835+-+n%29+%2B+0.05%2An+=+3.3

Now reduce the equation:

0.1%2A%2835+-+n%29+%2B+0.05%2An+=+3.5+-+0.1%2An+%2B+0.05%2An+=+3.5+-+0.05n

Subtract 3.5 from either side to get -0.05n+=+-0.2

divide both sides by -0.05 to get n = 4. If we have 4 nickels, we must have 31 dimes (n + d = 35). 31 dimes is $3.10 and 4 nickels is $0.20, so the total amount is $3.30.