SOLUTION: Jill has the same number of dimes as Jack has quarters. Jill has twice as many nickels as dimes. He also has 5 times as many pennies as dimes. Jill and Jack have the same amount

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Jill has the same number of dimes as Jack has quarters. Jill has twice as many nickels as dimes. He also has 5 times as many pennies as dimes. Jill and Jack have the same amount       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 230811: Jill has the same number of dimes as Jack has quarters. Jill has twice as many
nickels as dimes. He also has 5 times as many pennies as dimes. Jill and Jack
have the same amount of money. How much does each have?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Jill has the same number of dimes as Jack has quarters.
Jill has twice as many nickels as dimes.
He also has 5 times as many pennies as dimes.
Jill and Jack have the same amount of money.
How much does each have?
:
Let x = no. of dimes Jill has, and no. of quarters Jack has
Let n = no. of nickels, Jill has
Let p = no. of pennies Jack has
:
Jill has twice as many nickels as dimes.
n = 2x
:
He also has 5 times as many pennies as dimes. (Assume this is jill)
p = 5x
;
Jill and Jack have the same amount of money.
Jill$ = Jack$
.10x + .05n + .01p = .25x
Replace n with 2x and p with 5x
.10x + .05(2x) + .01(5x) = .25x
.10x + .10x + .05x = .25x; which true, but we still don't know what x is.
:
If we assume Jill has 10 nickels and Jack has 10 quarters
then
2(10) = 20 nickels for Jill
and
5(10) = 50 pennies for Jill
:
.05(20) + .10(10) + .01(50) = $2.50 Jill's total
and .25(10) = $2.50 Jack's total
:
But any value for x will work