SOLUTION: Sarah has $1015 in nickles, dimes, and quarters. She has twice as many dimes than nickles, and twice as many quarters than dimes. How many of each coin does she have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Sarah has $1015 in nickles, dimes, and quarters. She has twice as many dimes than nickles, and twice as many quarters than dimes. How many of each coin does she have?      Log On

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Question 183480: Sarah has $1015 in nickles, dimes, and quarters. She has twice as many dimes than nickles, and twice as many quarters than dimes. How many of each coin does she have?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let n= number of nickels she has
Let d= number of dimes she has
Let q= number of quarters she has
given:
(1) d+=+2n
(2) q+=+2d
(3) 5n+%2B+10d+%2B+25q+=+101500 (in cents)
Substitute (1) and (2) in (3)
(1) n+=+d%2F2
(3) 5n+%2B+10d+%2B+25q+=+101500
(3) 5%2A%28d%2F2%29+%2B+10d+%2B+25%2A%282d%29+=+101500
Multiply both sides by 2
(3) 5d+%2B+20d+%2B+100d+=+203000
(3) 125d+=+203000
(3) d+=+1624
Plug this result back into (1) and (2)
(1) n+=+d%2F2
(1) n+=+812
(2) q+=+2%2A1624
(2) q+=+3248
Sarah has 812 nickels, 1624 dimes, and 3248 quarters
check answer:
(3) 5n+%2B+10d+%2B+25q+=+101500
(3) 5%2A812+%2B+10%2A1624+%2B+25%2A3248+=+101500
(3) 4060+%2B+16240+%2B+81200+=+101500
(3) 101500+=+101500
OK