SOLUTION: A man went to pay for his lunch and found that he had exactly $1.00 with 11 coins. He had 3 kinds of coins and no more than 5 of any one kind. What coins did he have?

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Question 157308: A man went to pay for his lunch and found that he had exactly $1.00 with 11 coins. He had 3 kinds of coins and no more than 5 of any one kind. What coins did he have?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I'll start off assuming he had quarters, nickels, and dimes
Let q = number of quarters
Let d= number of dimes
Let n= number of nickels
I'll make a chart with q+%2B+d+%2B+n+=+11:
q - - d - - n - - sum
5 - - 5 - - 1 - - 1.80
4 - - 5 - - 2 - - 1.60
3 - - 5 - - 3 - - 1.40
3 - - 3 - - 5 - - 1.30
2 - - 5 - - 4 - - 1.20
1 - - 5 - - 5 - - 1.00
He has 1 quarter, 5 dimes, and 5 nickels