SOLUTION: A collection of nickels, dimes, and quarters amounts to $10.00. If there are 140 coins in all and there are twice as many dimes as there are quarters, find the number of nickels.
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Question 126860This question is from textbook Intermediate Algebra
: A collection of nickels, dimes, and quarters amounts to $10.00. If there are 140 coins in all and there are twice as many dimes as there are quarters, find the number of nickels. This question is from textbook Intermediate Algebra
You can put this solution on YOUR website! Let n=number of nickels, d=dimes, q=quarters
A) n+d+q=140
B) .05n+.1d+.25q=10
C) d=2q
.
A)
n+2q+q=140
n+3q=140
n=140-3q
.
B)
.05(140-3q)+.1(2q)+.25q=10
7-.15q+.2q+.25q=10
7+.3q=10
.3q=3
q=3/.3
q=10
.
C)
d=2*10
d=20
.
A)
n+20+10=140
n+30=140
n=110 Ans.
.
Check:
B)
.05*110+.1*20+.25*10=10
5.5+2+2.5=10 True
.
Ed
