SOLUTION: Kevin has (y-1) toonies and some quarters in his pocket. If the total amount of the coins is $0.25(8y+1)(y-1), how many quarters does Kevin have?

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Question 1162933: Kevin has (y-1) toonies and some quarters in his pocket. If the total amount of the coins is $0.25(8y+1)(y-1), how many quarters does Kevin have?
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


There is not enough information to find a unique solution....

(y-1) toonies (2 dollar coins), plus q quarters, equals 25(8y+1)(y-1) cents:

200%28y-1%29%2B25q+=+25%288y%2B1%29%28y-1%29
8%28y-1%29%2Bq+=+%288y%2B1%29%28y-1%29
q+=+%288y%2B1%29%28y-1%29-8%28y-1%29+=+%288y-7%29%28y-1%29

Any positive integer value for y gives a positive integer value for q, and all those q values are different.

(1)
y=2, so 1 toonie
(8y-7)(y-1) = (9)(1) = 9 quarters
1 toonie plus 9 quarters = 200+225 = 425 cents
25(8y+1)(y-1) = 25(17)(1) = 425 cents

(2)
y=3, so 2 toonies
(8y-7)(y-1) = (17)(2) = 34 quarters
2 toonies plus 34 quarters = 400+850 = 1250 cents
25(8y+1)(y-1) = 25(25)(2) = 1250 cents

(3)
y=4, so 3 toonies
(8y-7)(y-1) = (25)(3) = 75 quarters
3 toonies plus 75 quarters = 600+1875 = 2475 cents
25(8y+1)(y-1) = 25(33)(3) = 2475 cents

etc., etc., ....