SOLUTION: Kevin and Randy Muise have a jar containing
55
55 coins, all of which are either quarters or nickels. The total value of the coins in the jar is $
nbsp 8.55
8.55. How
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55
55 coins, all of which are either quarters or nickels. The total value of the coins in the jar is $
nbsp 8.55
8.55. How
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Question 1148716: Kevin and Randy Muise have a jar containing
55
55 coins, all of which are either quarters or nickels. The total value of the coins in the jar is $
nbsp 8.55
8.55. How many of each type of coin do they have? Answer by greenestamps(13203) (Show Source):
Let the number of quarters be x; then the number of nickels is (55-x).
The total value of the coins is $8.55, or 855 cents:
Solve using basic algebra....
Without algebra....
If all 55 coins were nickels, the value would be 55*5 = 275 cents.
The actual total value is 855 cents, which is 580 cents more than that.
Replacing a nickel with a quarter keeps the total number of coins the same but increases the total value by 20 cents.
The number of nickels that need to be replaced by quarters to make up the additional 580 cents is 580/20 = 29.
ANSWER: 29 quarters, 26 nickels.
CHECK: 29(25)+26(5) = 725+130 = 855
With all the words of explanation, that non-algebraic solution looks long. But here, without the words, are the simple calculations that are needed to find the solution.
