SOLUTION: Santos invests $7700 in two different accounts. The first account paid 11 %, the second account paid 2 % in interest. At the end of the first year he had earned $424 in interest. H

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Santos invests $7700 in two different accounts. The first account paid 11 %, the second account paid 2 % in interest. At the end of the first year he had earned $424 in interest. H      Log On

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Question 1129563: Santos invests $7700 in two different accounts. The first account paid 11 %, the second account paid 2 % in interest. At the end of the first year he had earned $424 in interest. How much was in each account?
At 11%-
At 2%-

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Santos invests $7700 in two different accounts.
let's say x is one account and y is other account

The first account paid 11 %, =0.11
the second account paid 2 % in interest=0.02

At the end of the first year he had earned $424 in interest.

x%2By=7700........eq.1->both sides multiply by 11
0.11x%2B0.02y=424......eq.2->both sides multiply by 100
--------------------------------------------------
11x%2B11y=84700........eq.1
11x%2B2y=42400......eq.2
----------------------------------------------------subtract
11x%2B11y-11x-2y=84700-42400
cross%2811x%29%2B11y-cross%2811x%29-2y=42300
9y=42300
y=42300%2F9
y=4700
then,
x%2By=7700...plug in y
x%2B4700=7700
x=7700-4700
x=3000

How much was in each account?
At 11%- was 3000-> got 330 in interest
At 2%- was 4700 -> got 94 in interest