SOLUTION: A merchant has coffee worth $20 a pound that she wishes to mix with 90 pounds of coffee worth $60 a pound to get a mixture that she will sell for $50 a pound. How many pounds (lb)

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: A merchant has coffee worth $20 a pound that she wishes to mix with 90 pounds of coffee worth $60 a pound to get a mixture that she will sell for $50 a pound. How many pounds (lb)       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1124019: A merchant has coffee worth $20 a pound that she wishes to mix with 90 pounds of coffee worth $60 a pound to get a mixture that she will sell for $50 a pound. How many pounds (lb) of the $20 coffee should be used?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = pounds of $20 coffee needed
————————-
+%28+20x+%2B+60%2A90+%29+%2F+%28+x+%2B+90+%29+=+50+
+20x+%2B+5400+=+50%2A%28+x+%2B+90+%29+
+20x+%2B+5400+=+50x+%2B+4500+
+30x+=+900+
+x+=+30+
30 pounds of the $20/lb coffee are needed
———————-
Check:
+%28+20%2A30+%2B+60%2A90+%29+%2F+%28+30+%2B+90+%29+=+50+
+6000+%2F+120+=+50+
+50+=+50+
OK