SOLUTION: He has 14 coins which is eithee 10 dollars or 2 dollars, total ampunt is not greater than 95, how many 10 coins he has?

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Question 1090020: He has 14 coins which is eithee 10 dollars or 2 dollars, total ampunt is not greater than 95, how many 10 coins he has?
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
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He has 14 coins highlight%28cross%28which%29%29 what highlight%28cross%28is%29%29 are highlight%28cross%28eithee%29%29 either 10 dollars or 2 dollars, total highlight%28cross%28ampunt%29%29 amount is not greater than 95, how many 10 coins he has?
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Let x = # of 10-dollar coins.
Then the number of 2-dollar coins is (14-x).


The value expression is value = 10x + 2*(14-x) dollars.


Your inequality is

10x + 2*(14-x) <= 95  ====>


Simplify and solve it step by step:


10x + 28 - 2x <= 95,

8x <= 95 - 28 = 67.  ====>  x <= 8


Answer.  Less than 9.

Solved.


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Regarding the answer by @MathTherapy, I want to underline one more time:

    The correct answer is "the number of 10-dollar coins is less than 9", 

    which means N <= 8,   BUT NOT NECESSARY N=8.


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
He has 14 coins which is eithee 10 dollars or 2 dollars, total ampunt is not greater than 95, how many 10 coins he has?
Number of $10 coins, with N being the number of $10 coins: .
This means that the number of ten-dollar coins, or: highlight_green%281+%3C=+N+%3C=+8%29 (The number of ten-dollar coins range from 1 to 8).