SOLUTION: emma has 4 more quarters than nickels. the total value of her quarters and nickels is $3.10. In all, what is the number of nickels that emma has? Please help me with the steps

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Question 1071754: emma has 4 more quarters than nickels. the total value of her quarters and nickels is $3.10. In all, what is the number of nickels that emma has?
Please help me with the steps to this problem

Found 2 solutions by stanbon, ikleyn:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
emma has 4 more quarters than nickels. the total value of her quarters and nickels is $3.10. In all, what is the number of nickels that emma has?
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q = n + 4
25q + 5n = 310 cents
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Substitute for "q" and solve for "n"::
25(n+4) + 5n = 310
25n + 100 + 5n = 310
30n = 210
n = 7 (# of nickels)
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Cheers,
Stan H.
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Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Take off the 4 quarters.


You will have new collection worth $3.10-$1.00 = $2.10, which consists of equal number of quarters and nickels.


Group the coins in the new collection in pairs, (one quarters and one nickel) in each pair.


Each pair is worth 25+5 = 30 cents.


How many pairs do you have? - Divide 210%2F30 and get 7: you have 7 pairs.


So, your original collection consists of 7 nickels and 7+4 = 11 quarters.

Solved.


There is entire bunch of lessons on coin problems
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
    - More complicated coin problems
    - Solving coin problems mentally by grouping without using equations
    - Santa Claus helps solving coin problem
    - OVERVIEW of lessons on coin word problems
in this site.

You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.

Read them and become an expert in solution of coin problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Coin problems".