SOLUTION: Keana’s piggy bank contains $4.30 in nickels and dimes only.  If she has 59 coins in her bank, then what is the sum of the digits in the number of nickels in Keana’s bank?  Write a

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Keana’s piggy bank contains $4.30 in nickels and dimes only.  If she has 59 coins in her bank, then what is the sum of the digits in the number of nickels in Keana’s bank?  Write a      Log On

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Question 1060910: Keana’s piggy bank contains $4.30 in nickels and dimes only.  If she has 59 coins in her bank, then what is the sum of the digits in the number of nickels in Keana’s bank?  Write a system of equations for this situation and find its solution.  

Found 2 solutions by algebrahouse.com, josmiceli:
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
n = number of nickels
d = number of dimes

n + d = 59 {she has 59 coins total}
5n + 10d = 430 {value of coin times number of coins equals total value}

-5n - 5d = -295 {multiplied top equation by -5}
5n + 10d = 430 {bottom equation stays the same}
---------------
5d = 135 {added the two equations}
d = 27 {divided each side by 5}

n + d = 59 {first original equation}
n + 27 = 59 {substituted 27, in for d, into first original equation}
n = 32 {subtracted 27 from each side}

27 dimes
32 nickels

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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +n+ = number of nickels
Let +d+ = number of dimes
--------------------------------
(1) +n+%2B+d+=+59+
(2) +5n+%2B+10d+=+430+
---------------------------
Subtract (1) from (2)
(2) +n+%2B+2d+=+86+
(1) +-n+-+d+=+-59+
----------------------
+d+=+27+
and
(1) +n+%2B+d+=+59+
(1) +n+%2B+27+=+59+
(1) +n+=+32+
+3+%2B+2+=+5+
The sum of the digits in number of nickels
is 5
---------------------
(2) +5n+%2B+10d+=+430+
(2) +5%2A32+%2B+10%2A27+=+430+
(2) +160+%2B+270+=+430+
(2) +430+=+430+
OK