SOLUTION: Ann has $7.20 worth of change in nickels and dimes. If she has four times as many nickels as dimes how many of each type of coin does she have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Ann has $7.20 worth of change in nickels and dimes. If she has four times as many nickels as dimes how many of each type of coin does she have?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1056158: Ann has $7.20 worth of change in nickels and dimes. If she has four times as many nickels as dimes how many of each type of coin does she have?
Found 2 solutions by ewatrrr, Alan3354:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x, the number of dimes
10x + 5(4x) = 720 CENTS makes sense
30x = 720
x = 24, number of dimes, 96nickels 4%2A24
checking:
240 + 480 = 720 CHECKS!

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Ann has $7.20 worth of change in nickels and dimes. If she has four times as many nickels as dimes how many of each type of coin does she have?
--------
Each set of 4 nickels and 1 dime = 30 cents.
720/30 = 24 sets