SOLUTION: Donald decided that it was time to break open his piggy bank. He had a mixture of pennies,nickels, dimes and quarters � at least four of each kind. When he counted them, he found

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Donald decided that it was time to break open his piggy bank. He had a mixture of pennies,nickels, dimes and quarters � at least four of each kind. When he counted them, he found      Log On

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Question 1028248: Donald decided that it was time to break open his piggy bank. He had a mixture of pennies,nickels, dimes and quarters � at least four of each kind. When he counted them, he found that he had exactly 100 coins with a value of $2.73.
How many of each coin does he have?

Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
p + n + d + q = 100
p + 5n + 10d + 25q = 273

one possible configuration:
p = 73 ---> 200 cents remaining
n = 20 ---> 100 cents remaining
d = 5 ---> 50 cents remaining
q = 2 ---> 0 cents remaining