Let the number of quarters be x
Let the number of dimes be y
Value Value
Type Number of of
of of EACH ALL
coin coins coin coins
-------------------------------------------
quarters x $0.25 $0.25x
dimes y $0.10 $0.10y
-------------------------------------------
TOTALS 17 ----- $3.50
The first equation comes from the "Number of coins"
column.
x + y = 17
The second equation comes from the last column.
0.25x + 0.10y = 3.50
Get rid of decimals by multiplying every term by 100:
25x + 10y = 350
So we have the system of equations:
.
We solve by substitution. Solve the first equation for y:
x + y = 17
y = 17 - x
Substitute (17 - x) for y in 25x + 10y = 350
25x + 10(17 - x) = 350
25x + 170 - 10x = 350
15x + 170 = 350
15x = 180
x = 12 = the number of quarters.
Substitute in y = 17 - x
y = 17 - (12)
y = 5 dimes.
Checking: 12 quarters is $3.00 and 5 dimes is $0.50
That's 17 coins.
And indeed $3.00 + $0.50 = $3.50
Edwin