SOLUTION: A man has 30 coins in his pocket, all of which are dimes and quarters. If the total value of his change is 465 cents, how many dimes and how many quarters does he have?
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: A man has 30 coins in his pocket, all of which are dimes and quarters. If the total value of his change is 465 cents, how many dimes and how many quarters does he have?
Log On
Question 1017226: A man has 30 coins in his pocket, all of which are dimes and quarters. If the total value of his change is 465 cents, how many dimes and how many quarters does he have? Answer by Edwin McCravy(20056) (Show Source):
Let the number of dimes be x
Let the number of quarters be y
Value Value
Type Number of of
of of EACH ALL
coin coins coin coins
-------------------------------------------
dimes x $0.10 $0.10x
quarters y $0.25 $0.25y
-------------------------------------------
TOTALS 30 ----- $4.65
The first equation comes from the second column.
x + y = 30
The second equation comes from the last column.
0.1x + 0.25y = 4.65
Get rid of decimals by multiplying every term by 100:
10x + 25y = 465
So we have the system of equations:
.
We solve by substitution. Solve the first equation for y:
x + y = 30
y = 30 - x
Substitute (30 - x) for y in 10x + 25y = 465
10x + 25(30 - x) = 465
10x + 750 - 25x = 465
-15x + 750 = 465
-15x = -285
x = 19 = the number of dimes.
Substitute in y = 30 - x
y = 30 - (19
y = 11 quarters.
Checking: 19 dimes is $1.90 and 11 quarters is $2.75
That's 30 coins.
And indeed $1.90 + $2.75 = $4.65
Edwin