Tutors Answer Your Questions about Age Word Problems (FREE)
Question 824184: The father and the son together have 46 years. Three years ago, the father was 4 times older than the son. How old is the son, and how old is the father?
So, I tried to find a solution.
3 years ago
father 4x
son x
now
father 46-x
son x
4x+3+x+3=46-x+x
5x+6=46 (I omitted the -x and the x)
5x=46-6
5x=40
x=40/5
x=8
So the son is 8 years old and the father is 46-8=38.
Actually, my question is - is my solution right (correct)?
Click here to see answer by josmiceli(19441)  |
Question 824483: tommy: how old are you momma?
momma? your age my age and your fathers age equal 70.
tommy: how old are you papa?
papa: just six times as old as you papa
tommy: will i ever be half your age?
papa: that should happen when our three ages equal twice as much as it does today.
how old is papa momma and tommy?
Click here to see answer by josmiceli(19441)  |
Question 824776: Mary is N years old and her husband is 4 years older than her. The sum of their ages is 58 years old. What is N? The boy is now N years old and his father is 30 years old. In 5 years the son will be ___ years old and his father will be ___ years old. Therefore, __________ N=____
Click here to see answer by phoihe001(34)  |
Question 825406: Michelle has a patty and invites 3 friends. Each friend invites 3 other friends. each of these friends invites 3 more friends. Finally,each of these friends invites 3 more friends. Each guest at the party brings 3 gifts, with 3 bows on each gift. How many bows does Michelle get at the party?
Click here to see answer by stanbon(75887) |
Question 825406: Michelle has a patty and invites 3 friends. Each friend invites 3 other friends. each of these friends invites 3 more friends. Finally,each of these friends invites 3 more friends. Each guest at the party brings 3 gifts, with 3 bows on each gift. How many bows does Michelle get at the party?
Click here to see answer by josmiceli(19441)  |
Question 825532: I have trouble with this question:
The ages of Peter, Margaret and Jack are consecutive odd numbers. The sum of the ages of Peter and Margaret equals Jack’s age before 5 years. Find the ages of Peter, Margaret and Jack.
I don't know how to consider the "consecutive odd numbers" but I know the second equation is p + m = j - 5
How do you solve the rest of this problem?
Thank you.
Click here to see answer by rothauserc(4718)  |
Question 825527: Hello, I have just starting practicing and now improving on "age" word problems. But I am stuck on this one question:
Nick and Kane were born on consecutive years and on same date. Nick is younger. The sum of their ages is 11. Find the age of the brothers.
I get confused with the word "consecutive" in a sentence. However, I had a go:
n = k - 1 (I assume that Nick is younger by a year but the I am not too sure of the number)
n + k = 11 (the sum of both the brothers' ages)
Sub n = k - 1 into n + k = 11
k - 1 + k = 11
2k - 1 = 11
2k = 12
k = 6
Nick would have to be 5 years old.
Does this sound right to you?
Click here to see answer by rothauserc(4718)  |
Question 825771: Hello,
I did ask this question: The ages of Peter, Margaret and Jack are consecutive odd numbers. The sum of the ages of Peter and Margaret equals Jack’s age before 5 years. Find the ages of Peter, Margaret and Jack.
I read the solution but I don't know how you get the consecutive numbers: x, x + 2 and x + 4. Can you please explain to me why?
Thank you.
Click here to see answer by richwmiller(17219)  |
Question 825774: The sum of the ages of Tony and Teddy equals thrice their mother’s age. Tony is two years younger than Teddy. If the age of the mother is 42, find the ages of Tony and Teddy.
I've done:
t + d = 3m
t = d - 2
m = 42
I "plugged" in the numbers but the numbers are really high at the end. What am I doing wrong here?
Thank you.
Click here to see answer by stanbon(75887) |
Question 825853: The average age of five boys is 15 years. A sixth boy joins them, making the average age 15 years and 6 months. What is the age of this sixth boy?
Please reply as soon as possible because I am applying for Bergen Academies and I need help and I would really appreciate.
Thankyou!
My work:
15*5=75
75x=186
x=2.48
It is a impossible for the sixth boy to be 2.48 years old, therefore i find it difficult to complete this problem...
Click here to see answer by KMST(5328)  |
Question 825889: The average age of six children is 13 years and 5 months. A seventh child joins the group, increasing the average age by two months. How old is this seventh child?
My work:
2*6=12months (1year)
5+2=2 months
Answer= 13 years 7 months (after adding the two months)= 14 years 7 months
Is that correct thank you!!!
If there is a different method please let me know!!!
Gracias!!!
Click here to see answer by josmiceli(19441)  |
Question 825889: The average age of six children is 13 years and 5 months. A seventh child joins the group, increasing the average age by two months. How old is this seventh child?
My work:
2*6=12months (1year)
5+2=2 months
Answer= 13 years 7 months (after adding the two months)= 14 years 7 months
Is that correct thank you!!!
If there is a different method please let me know!!!
Gracias!!!
Click here to see answer by Fermat(136)  |
Question 826096: the coin collection was being sold. chloe bought half of the coins plus 5 more, then steve bought 5, then kirk bought 10 more than half of what was left, and then jesscia bought 25. leaving 10 unsold. how many coins where there orginally?
Click here to see answer by Edwin McCravy(20060)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 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