SOLUTION: Five years ago a mother was twice as old as her son in six years time the sum of their ages will be 82. Find their present ages.

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Question 999302: Five years ago a mother was twice as old as her son in six years time the sum of their ages will be 82. Find their present ages.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Five years ago a mother was twice as old as her son.
In six years time the sum of their ages will be 82.
Find their present ages.
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Equations:
m-5 = 2(s-5)
m+6 + s+6 = 82
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Rearrange::
m - 2s = -5
m + s = 70
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Subtract and solve for "s":
3s = 75
son's age = 25 yrs
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Solve for "m":
m + s = 70
mother's age = 55 yrs
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Cheers,
Stan H.