SOLUTION: JOHNS FATHER IS 5 TIMES OLDER THAN JOHN AND JOHN IS TWICE AS OLD AS HER SISTER ALICE. IN TWO YEARS TIME, THE SUM OF THEIR AGES WILL BE 58

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Question 991042: JOHNS FATHER IS 5 TIMES OLDER THAN JOHN AND JOHN IS TWICE AS OLD AS HER SISTER ALICE. IN TWO YEARS TIME, THE SUM OF THEIR AGES WILL BE 58
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If I read this right, when it says:
" The sum of THEIR ages will be 58 ", THEIR
means all 3 of them
-----------------------
Let +j+ = John's age now
Let +f+ = His father's age now
Let +s+ = John's sister's age now
------------------------------
(1) +f+=+5j+
(2) +j+=+2s+
(3) +%28+j+%2B+2+%29+%2B+%28+f+%2B+2+%29+%2B+%28+s+%2B+2+%29+=+58+
-----------------------------------
(3) +j+%2B+f+%2B+s+%2B+6+=+58+
(3) +j+%2B+f+%2B+s+=+52+
and
(2) +s+=+j%2F2+
Substitute (1) and (2) into (3)
(3) +j+%2B+5j+%2B+j%2F2+=+52+
(3) +2j+%2B+10j+%2B+j+=+104+
(3) +13j+=+104+
(3) +j+=+8+
and
(2) +s+=+j%2F2+
(2) +s+=+4+
and
(1) +f+=+5j+
(1) +f+=+5%2A8+
(1) +f+=+40+
John is 8
John's sister is 4
John's father is 40
------------------
check answer:
(3) +%28+j+%2B+2+%29+%2B+%28+f+%2B+2+%29+%2B+%28+s+%2B+2+%29+=+58+
(3) +%28+8+%2B+2+%29+%2B+%28+40+%2B+2+%29+%2B+%28+4+%2B+2+%29+=+58+
(3) +10+%2B+42+%2B+6+=+58+
(3) +58+=+58+
OK