SOLUTION: tom is four less than twice gary's age. rebecca is the youngest and she is two less than half gary's age after it was increased by three. sam's age is the ratio of seven more than

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Question 979938: tom is four less than twice gary's age. rebecca is the youngest and she is two less than half gary's age after it was increased by three. sam's age is the ratio of seven more than gary's age to eight less than gary's age.
how do I translate each of their ages into algebraic expressions?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
let t = Tom's age
let g = Gary's age
let r = Reb's age
let s = Sam's age
:
tom is four less than twice gary's age.
t = 2g - 4
:
Gary's age
2g - 4 = t
2g = t + 4
g = %28%28t%2B4%29%29%2F2
:
rebecca is the youngest and she is two less than half gary's age after it was increased by three.
r = .5(g+3) -2
:
sam's age is the ratio of seven more than gary's age to eight less than gary's age.
s = %28%28g%2B7%29%29%2F%28%28g-8%29%29