SOLUTION: A woman has a son and a daughter. The mother is three times as old as her son. The son is seven years older then the daughter. Three years from now the boy will be twice as old as
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Question 976963: A woman has a son and a daughter. The mother is three times as old as her son. The son is seven years older then the daughter. Three years from now the boy will be twice as old as his sister will be. What are the three linear equations for this problem ? Found 2 solutions by FrankM, lwsshak3:Answer by FrankM(1040) (Show Source):
You can put this solution on YOUR website! M=3S
S=D+7
S+3=2(D+3)
Above is the answer. To complete the problem, we can add 3 to the second equation, both sides.
S+3=D+10
Then set an equation as follows:
2(D+3)=D+10
2D+6=D+10
D=4, S=11, M=33
You can put this solution on YOUR website! A woman has a son and a daughter. The mother is three times as old as her son. The son is seven years older then the daughter. Three years from now the boy will be twice as old as his sister will be. What are the three linear equations for this problem ?
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let x=son's age
3x= mother's age
x-7=daughter's age
..
3 yrs from now:
x+3=son's age
x-7+3=x-4=daughter's age
x+3=2(x-4)
x+3=2x-8
x=11
son's age=11
mother's age=33
daughter's age=4
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