SOLUTION: A man has 3 children namely Ade, Femi, and Funmi. Ade is a year older than Femi and Femi in turn is twelve years older than Funmi. The sum of their ages is 28 years.How old is each

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Question 976087: A man has 3 children namely Ade, Femi, and Funmi. Ade is a year older than Femi and Femi in turn is twelve years older than Funmi. The sum of their ages is 28 years.How old is each child now.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = Ade's age now
Let +b+ = Femi's age now
Let +c+ = Funmi's age now
--------------------------
(1) +a+%2B+b+%2B+c+=+28+
(2) +a+=+b+%2B+1+
(3) +b+=+c+%2B+12+
------------------
(3) +c+=+b+-+12+
Substitute (2) and (3) into (1)
(1) +b+%2B+1+%2B+b+%2B+b+-+12+=+28+
(1) +3b+-+11+=+28+
(1) +3b+=+39+
(1) +b+=+13+
and
(2) +a+=+13+%2B+1+
(2) +a+=+14+
and
(3) +c+=+13+-+12+
(3) +c+=+1+
---------------
Ade is 14
Femi is 13
Funmi is 1
------------
check:
(1) +a+%2B+b+%2B+c+=+28+
(1) +14+%2B+13+%2B+1+=+28+
(1) +28+=+28+
OK