SOLUTION: A32 year old mother realized that her age is twice the sum of her two children's age. Her son jose is two years older than.her daughter sophia.
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Question 967961: A32 year old mother realized that her age is twice the sum of her two children's age. Her son jose is two years older than.her daughter sophia. Answer by macston(5194) (Show Source):
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S=Sophia's age; J=Jose's age=S+2yrs
2(S+J)=32 years Substitute for J
2(S+S+2yrs)=32 years
2(2S+2yrs)=32 years
4S+4yrs=32 years Subtract 4 years from each side.
4S=28 years Divide each side by 4
S=7 years ANSWER 1: Sophia is 7 years old.
J=S+2yrs=7yrs+2yrs=9yrs ANSWER 2: Jose is 9 years old.
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CHECK:
2(S+J)=32 years
2(7yrs+9yrs)=32 years
2(16yrs)=32 years
32 years=32 years
