SOLUTION: Jason's age is 3 times Shauna's present age. In 4 years time, the sum of their ages will be 56 years. Find their present age.
**Help me please!! I need to be able to determin
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**Help me please!! I need to be able to determin
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Question 947745: Jason's age is 3 times Shauna's present age. In 4 years time, the sum of their ages will be 56 years. Find their present age.
**Help me please!! I need to be able to determine both of their ages and write down an Algebraic Equation!!**
Thank You 😜 Found 2 solutions by ankor@dixie-net.com, josgarithmetic:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! let j = Jason's present age
let s = Shauna's age
:
Write an equation for each statement
:
"Jason's age is 3 times Shauna's present age."
j = 3s
" In 4 years time, the sum of their ages will be 56 years."
4 yrs later
(j+4) + (s+4) = 56
j + s + 8 = 56
j + s = 56 - 8
j + s = 48
substitute 3s for j from the 1st statement
3s + s = 48
4s = 48
s = 48/4
s = 12 yrs is Shauna's age
then
3(12) = 36 yrs is Jason's age
;
:
See if the this checks out in the 2nd statement
(36 + 4) + (12 + 4) =
40 + 16 = 56
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