Question 947305: A father is 6 times as old as his son. Three years ago , the father was 9 times as old as his son. Find the present age of each. Answer by amarjeeth123(569) (Show Source):
You can put this solution on YOUR website! Let the son's age be x.
The father's age is 6x.
Three years ago the father's age is (6x-3)
Three years ago the son's age is x-3.
6x-3=9(x-3)
6x-3=9x-27
3x=24
x=8
The father's age is 48 years and the son's age is 8 years.
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