Question 939990: today, a father is 10 years older than twice his son's age. five years a go, the product of their ages was 350. how old is his son now today, a father is 10 years older than twice his son's age. five years a go, the product of their ages was 350. how old is his son now
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! today, a father is 10 years older than twice his son's age. five years a go, the product of their ages was 350. how old is his son now
-----
Equations::
f = 2s+10
(f-5)(s-5) = 350
-------
Substitute for "f" and solve for "s"::
(2s+5)(s-5) = 350
2s^2 -5s -375 = 0
------
s = 15 yrs (son's age now)
------------------
Cheers,
Stan H.
-------------
|
|
|
