SOLUTION: if 7 apples and 2 oranges costs 114 while 6 apples and 4 oranges cost 132, how much does one apple and one orange cost?

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Question 939041: if 7 apples and 2 oranges costs 114 while 6 apples and 4 oranges cost 132, how much does one apple and one orange cost?
Found 2 solutions by josgarithmetic, lwsshak3:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
a, price for one apple
n, price for one orange

system%287a%2B2n=114%2C6a%2B4n=132%29

Two linear equations in two unknown variables. Need more help?
If you simplify the "132" equation, you can easily use Elimination Method...

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
if 7 apples and 2 oranges costs 114 while 6 apples and 4 oranges cost 132, how much does one apple and one orange cost?
Your total cost in dollars for apples and oranges is a bit high, so I will use reasonable costs of $11.40 and $13.20 instead.
***
let a=cost of one apple
let o=cost of ome orange
..
7a+2o=11.40
6a+4o=13.20
..
14a+4o=22.80(mult. eq by 2)
6a+4o=13.20
subtract:
8a=9.60
a=1.20
2o=11.40-7a=11.40-8.40=3.00
o=1.50
cost of one apple=$1.20
cost of one orange=$1.50
These are very expensive apples and oranges