SOLUTION: 1. There are 6 fangos in a rango and 15 rangos in a bango. a. Alex has 9 rangos and 4 fangos. Barbara has 7 rangos and 3 fangos. How many fangos do they both have in total? b. W

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Question 936014: 1. There are 6 fangos in a rango and 15 rangos in a bango.
a. Alex has 9 rangos and 4 fangos. Barbara has 7 rangos and 3 fangos. How many fangos do they both have in total?
b. What fraction of a bango do 12 fangos represent?
c. How many whole bangos are there in 274 fangos? How many fangos are left over?
2. AB + C = 50
BC + A = 41
WHAT IS THE VALUE OF A, B AND C?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
1. let rangos be R, fangos F, and a bango B
R=6F......eq.1
B=15R.....eq.2
-------------------


a. Alex has 9 rangos and 4 fangos.
Barbara has 7 rangos and 3 fangos.

Alex=9R%2B4F..........substitute R from eq.1
Alex=9%2A6F%2B4F=54F%2B4F=58F
Barbara=7R%2B3F=7%2A6F%2B4F=42F%2B4F=46F
so, Alex%2BBarbara=58F%2B46F=104F

2.
easy
A = 41
B = 0
C = 50
proof:
AB%2BC=50................eq.1
BC%2BA=41.............eq.2


AB%2BC=50 ......eq.1 ...........solve for+C
C=50-AB..substitute in eg.2

B%2850-AB%29%2BA=41......eq.2

50B-AB%5E2%2BA=41....solve for A

50B-A%28B%5E2-1%29=41

50B=41%2BA%28B%5E2-1%29

50B-41=A%28B%5E2-1%29

A=%2850B-41%29%2F%28B%5E2-1%29

then C=50-%28%2850B-41%29%2F%28B%5E2-1%29%29B

go to
AB%2BC=50....eq.1 substitute A and C

%28%2850B-41%29%2F%28B%5E2-1%29%29B%2B50-%28%2850B-41%29%2F%28B%5E2-1%29%29B=50

%28%2850B-41%29B%2B50%28B%5E2-1%29-%2850B-41%29B%29%2F%28B%5E2-1%29=50

%2850B%5E2-41B%2B50B%5E2-50-50B%5E2%2B41B%29%2F%28B%5E2-1%29=50

-50%2F%28B%5E2-1%29=50

-50=50%28B%5E2-1%29

-1=B%5E2-1

-1%2B1=B%5E2

0=B%5E2
=> highlight%28B=0%29

then C=50-%2850B-41%29%2F%28B%5E2-1%29B
+C=50-%2850%2A0-41%29%2F%280%5E2-1%29%2A0
+C=50-%28-41%2F-1%29%2A0
+C=50-0
+highlight%28C=50%29
and
A=%2850B-41%29%2F%28B%5E2-1%29
A=%2850%2A0-41%29%2F%280%5E2-1%29
A=-41%2F-1
highlight%28A=41%29