SOLUTION: three brothers have ages that are consecutive odd intergers. the difference between the age of the oldest and twice the age of the youngest is twenty four less than the middle brot

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: three brothers have ages that are consecutive odd intergers. the difference between the age of the oldest and twice the age of the youngest is twenty four less than the middle brot      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 934957: three brothers have ages that are consecutive odd intergers. the difference between the age of the oldest and twice the age of the youngest is twenty four less than the middle brothers age. find their ages
Answer by vicgonzerx(31) About Me  (Show Source):
You can put this solution on YOUR website!
X=YOUNGEST
X+2=MIDDLE
X+4=OLDEST
X+4-2X=X+2-24
2X=26
X=13
X+2=15
X+4=17
THE AGE ARE 13,15,17