SOLUTION: Mr. Jackson is 13 years less than 3 times as old as his son. Six years ago, he was 14 more than twice as old as his son then. Find each of their ages.
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Question 934197: Mr. Jackson is 13 years less than 3 times as old as his son. Six years ago, he was 14 more than twice as old as his son then. Find each of their ages.
You can put this solution on YOUR website! Mr. Jackson is 13 years less than 3 times as old as his son. Six years ago, he was 14 more than twice as old as his son then. Find each of their ages.
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Equations:
J = 3S - 13
J-6 = 2(S-6)+14
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Substitute for "J" and solve for "S.
3S-13-6 = 2S-12+14
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S = -8+19
Son's age = 11 yrs
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Solve for "J"::
J = 3S-13
J = 33-13 = 20 yrs (Mr. Jackson's age now)
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Cheers,
Stan H.
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